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<channel>
	<title>The Prodigal Physicist</title>
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	<link>http://joefilippazzo.com</link>
	<description></description>
	<pubDate>Mon, 20 Oct 2008 20:52:14 +0000</pubDate>
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	<language>en</language>
			<item>
		<title>Work and Energy</title>
		<link>http://joefilippazzo.com/2008/work-and-energy/</link>
		<comments>http://joefilippazzo.com/2008/work-and-energy/#comments</comments>
		<pubDate>Thu, 18 Sep 2008 14:55:28 +0000</pubDate>
		<dc:creator>Joe</dc:creator>
		
		<category><![CDATA[Classical Mechanics]]></category>

		<category><![CDATA[center of mass]]></category>

		<category><![CDATA[energy]]></category>

		<category><![CDATA[equilibrium]]></category>

		<category><![CDATA[inertia]]></category>

		<category><![CDATA[kinetic energy]]></category>

		<category><![CDATA[potential energy]]></category>

		<category><![CDATA[work]]></category>

		<category><![CDATA[Work and Energy Theorem]]></category>

		<guid isPermaLink="false">http://joefilippazzo.com/?p=62</guid>
		<description><![CDATA[Classical physics = work and energy. This is a solid treatment of the theorems, equations and derivations involved in this most important of classical physics topics. Here we cover kinetic and potential energy, inertia and comprehensive, multi-step solutions to simple physical systems.]]></description>
			<content:encoded><![CDATA[<p>Mechanical work is the energy transferred by a force <strong><em>F</em></strong> over a displacement <strong><em>d</em></strong>. Work is a scalar quantity (since it&#8217;s <a href="http://www.joefilippazzo.com/2008/vectors/#vectormultiplication">the dot product of two vectors</a>) and we can derive the theorem very easily.</p>
<p>Multiplying both sides of &#8220;eff-equals-em-ey&#8221; by a tiny displacement in the (let&#8217;s say) x direction, we get:</p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&#038;eq=F_x%5CDelta%7Bx%7D%3Dma%5CDelta%7Bx%7D%3Dma(x_2-x_1)"></p>
<p>We know from the <a href="http://www.joefilippazzo.com/2008/kinematics/#eqofmotion">equations of motion</a>,</p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&#038;eq=v%5E2%3Dv_0%5E2%2B2a(x_2-x_1)%5Chspace%7B10%20mm%7Dso%2C%5Chspace%7B10%20mm%7Da(x_2-x_1)%3D%5Cfrac%7B1%7D%7B2%7Dv%5E2-%5Cfrac%7B1%7D%7B2%7Dv_0%5E2"></p>
<p>Substituting for <img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&#038;eq=a(x_2-x_1)"> we get,</p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&#038;eq=%5Ctextbf%7BF%7D%5Ccdot%5Ctextbf%7Bd%7D%3D%5Cfrac%7B1%7D%7B2%7Dmv_2%5E2-%5Cfrac%7B1%7D%7B2%7Dmv_1%5E2"></p>
<p>Now we see that work here is just the change in kinetic energy. When we include non-conservative (NC) friction (as true physical systems do) we get some definitions for work:</p>
<ul><strong>The Work and Energy Theorem</strong></p>
<li><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&#038;eq=W_%7BNC%7D%3D%5CDelta%7BE_k%7D%2B%5CDelta%7BU%7D"></li>
<li><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&#038;eq=W%5Cequiv%5Cint%5Ctextbf%7BF%7D%5Ccdot%7Bd%7D%5Ctextbf%7Br%7D"></li>
<li><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&#038;eq=%5CDelta%7BU%7D%5Cequiv-%5Cint%5Ctextbf%7BF%7D%5Ccdot%7Bd%7D%5Ctextbf%7Br%7D"></li>
</ul>
<p>Here, <em>U</em> is the potential energy and <em>E<sub>k</sub></em> is the kinetic energy. Using the definition of the potential energy above, we can find the <em>U</em> associated with any force by integrating. The table below shows a few examples:</p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&#038;eq=%5Cbegin%7Barray%7D%7B%20l%20%20c%20%20c%20%20%7D%0A%20%20%5Cmbox%7Bforce%7D%20%26%20F%20%26%20U%20%5C%5C%0A%5Chline%0A%5Cvspace%7B4%20mm%7D%0A%20%20%5Cmbox%7Bgravity%7D%20%26%20-mg%20%26%20mgy%20%5C%5C%0A%5Cvspace%7B4%20mm%7D%0A%20%20%5Cmbox%7Bspring%7D%20%26%20-kx%20%26%20%5Cfrac%7B1%7D%7B2%7Dkx%5E2%20%5C%5C%0A%20%20%5Cmbox%7BNewtonian%20gravity%7D%20%26%20%5Cfrac%7BGMm%7D%7Br%5E2%7D%20%26%20-%5Cfrac%7BGMm%7D%7Br%7D%0A%5Cend%7Barray%7D" class="center"></p>
]]></content:encoded>
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		</item>
		<item>
		<title>Newton&#8217;s Laws</title>
		<link>http://joefilippazzo.com/2008/newtons-laws/</link>
		<comments>http://joefilippazzo.com/2008/newtons-laws/#comments</comments>
		<pubDate>Tue, 12 Aug 2008 18:02:18 +0000</pubDate>
		<dc:creator>Joe</dc:creator>
		
		<category><![CDATA[Classical Mechanics]]></category>

		<category><![CDATA[F=ma]]></category>

		<category><![CDATA[G (gravitational constant)]]></category>

		<category><![CDATA[Kepler's Law]]></category>

		<category><![CDATA[kinetic friction]]></category>

		<category><![CDATA[Newton (unit)]]></category>

		<category><![CDATA[newtonian gravity]]></category>

		<category><![CDATA[static friction]]></category>

		<category><![CDATA[tension]]></category>

		<guid isPermaLink="false">http://joefilippazzo.com/?p=45</guid>
		<description><![CDATA[Pulleys, inclined planes, sliding blocks, friction! This post has it all! We also include a bunch of fully explained examples and introduce Newtonian Gravity and Kepler's Laws. There's also a Honeymooners reference for kicks. Leave some comments!]]></description>
			<content:encoded><![CDATA[<p>Finally, some nuts and bolts physics! We&#8217;ll fly through this grade school stuff post-haste and I&#8217;ll try to stick to the heart-pounding, edge-of-your-seat, action-packed examples so you don&#8217;t fall asleep.</p>
<ul><strong>There are three laws at the heart of Newtonian mechanics:</strong></p>
<li>An object keeps its state of motion unless acted upon by an external force</li>
<li><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=%5Csum%7B%5Ctextbf%7BF%7D%7D%3Dm%5Ctextbf%7Ba%7D" alt="" /></li>
<li>For every force, there is an equal and opposite force</li>
</ul>
<p>The second of these laws is the omnipotent and ubiquitous &#8220;eff-equals-em-ey&#8221; which just means that the sum of all vector forces equals the scalar mass times the sum of all vector accelerations.</p>
<p>For absolutely any classical problem, set up a free body diagram (a simple illustration of the magnitude and direction of all the vectors), add up the forces in each dimension and evaluate. Check it out:</p>
<h3>example: <span style="color: green;">ice block</span></h3>
<p><strong>Viewed from above, a 10kg block of ice is resting on a sheet of ice. (Forgive the contrived example. The point is, it&#8217;s frictionless!) What is the acceleration in the x and y directions?</strong></p>
<p><img title="Ex: Ice Block" src="http://joefilippazzo.com/wp-content/uploads/2008/08/ice_cube.jpg" alt="" width="400" /></p>
<p>First, the x component:</p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=%5Csum%20F_x%3Dma_x%20" alt="" /></p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=25%2B15cos20%2B20cos60%3D10a_x" alt="" /></p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=a_x%3D4.4m%2Fs%5E2" alt="" /></p>
<p>Then the y component:</p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=%5Csum%20F_y%3Dma_y" alt="" /></p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=15sin20-20sin60%3D10a_y" alt="" /></p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=a_y%3D-1.22m%2Fs%5E2" alt="" /></p>
<p>Then the magnitude of the vector <strong>a</strong> is:</p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=%7C%5Ctextbf%7Ba%7D%7C%3D%5Csqrt%7B%7Ba_x%7D%5E2%2B%7Ba_y%7D%5E2%7D%3D%5Csqrt%7B(4.4)%5E2%2B(-1.22)%5E2%7D%3D%5Csqrt%7B19.36%2B1.49%7D%3D4.57m%2Fs%5E2" alt="" /></p>
<p>And the angle from the x axis is:</p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=tan%5Ctheta_a%3D%5Cfrac%7Ba_y%7D%7Ba_x%7D%3D%5Cfrac%7B-1.22%7D%7B4.4%7D%3D-0.277" alt="" /></p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=%5Ctheta_a%3Dtan%5E%7B-1%7D(-.277)%5Capprox-51%5E%5Ccirc" alt="" /></p>
<h3>example: <span style="color: green;">frictionless pulley</span></h3>
<p><strong>What is the acceleration of both weights?</strong></p>
<p><img title="Ex: Frictionless Pulley" src="http://joefilippazzo.com/wp-content/uploads/2008/08/frictionless_pulley.jpg" alt="" width="225" /><br />
For this problem, our (frictionless) pulley only allows forces in the ±y direction. Let&#8217;s look at the problem as a free body diagram:</p>
<p><img title="free body diagram for the Frictionless Pulley" src="http://joefilippazzo.com/wp-content/uploads/2008/08/pulley_fbd.jpg" alt="" width="250" /></p>
<p><strong><em>T</em></strong> here is the tension on the rope and <strong><em>g</em></strong> is always the acceleration due to gravity. On the left we have:</p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&#038;eq=%5Csum%5Ctextbf%7BF%7D%3Dm%5Ctextbf%7Ba%7D%3D10%5Ctextbf%7Bg%7D-%5Ctextbf%7BT%7D%3D10%5Ctextbf%7Ba%7D" alt="" /></p>
<p>And on the right we have:</p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&#038;eq=%5Csum%5Ctextbf%7BF%7D%3Dm%5Ctextbf%7Ba%7D%3D%5Ctextbf%7BT%7D-5%5Ctextbf%7Bg%7D%3D5%5Ctextbf%7Ba%7D" /></p>
<p>Solving the above for <strong><em>T</em></strong>, then plugging it into the first equation, we get:</p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=10%5Ctextbf%7Bg%7D-(5%5Ctextbf%7Ba%7D%2B5%5Ctextbf%7Bg%7D)%3D10%5Ctextbf%7Ba%7D%5C%5C" alt="" /></p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=98-49%3D10%5Ctextbf%7Ba%7D%2B5%5Ctextbf%7Ba%7D" alt="" /></p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=%5Ctextbf%7Ba%7D%3D%5Cfrac%7B49%7D%7B15%7D%3D3.27m%2Fs%5E2" alt="" /></p>
<p>So, the 10kg weight accelerates down (+y) on the left and the 5kg weight accelerates up (+y) on the right, both with the acceleration <strong><em>a</em></strong>.</p>
<p>You may say, &#8220;Of course they accelerate at the same rate, jerk.&#8221; Or &#8220;The heavier one <em>has to</em> pull the lighter one down.&#8221; But these are easy things to overlook. Anytime you&#8217;re working out a problem, take a step back and try to think intuitively about the (no pun intended) forces at work. &#8220;What&#8217;s happening in this situation?&#8221; is a great question to keep asking yourself.</p>
<p>The thicket of mathematics has many brambles. Don&#8217;t get stuck in the equations!</p>
<h3>friction</h3>
<p>For some more realistic calculations, let&#8217;s work friction into the mix. The two types of friction are static and kinetic and the equations of force are as follows:</p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=%5Ctextbf%7BF%7D_s%5Cle%5Cmu_s%5Ctextbf%7BN%7D%5Chspace%7B20%20mm%7D%5Ctextbf%7BF%7D_k%3D%5Cmu_k%5Ctextbf%7BN%7D%5Chspace%7B20%20mm%7D%5Cmu_k%3C%5Cmu_s" alt="" /></p>
<p>Here <em>μ<sub>s</sub></em> is the coefficient of static friction, <em>μ<sub>k</sub></em> is the coefficient of kinetic friction and <strong><em>N</em></strong> is the normal (the &#8220;equal and opposite force&#8221; to the block&#8217;s weight).<br />
<em><br />
μ<sub>s</sub></em> is the force a body must overcome to move from a (static) state of rest. <em>μ<sub>k</sub></em> is the force that decelerates a moving (kinetic) body. The inequality of the coefficients represents the &#8220;bump&#8221; that you feel when you decelerate and stop completely.</p>
<h3>example: <span style="color: green;">inclined plane</span></h3>
<p><strong>What is the acceleration of the blocks?</strong></p>
<p><img title="Ex: Inclined Plane" src="http://joefilippazzo.com/wp-content/uploads/2008/08/inclined_plane.jpg" alt="" width="475" /></p>
<p>Like always, let&#8217;s take each block separately, create a free body diagram to evaluate the x and y contributions and then add it all up.</p>
<p>For the 10kg block, which only moves in the y direction, we have:</p>
<p><img src="http://joefilippazzo.com/wp-content/uploads/2008/08/10kg_block.jpg" title="free body diagram for the 10kg block" width="130" /></p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=x%3A%5Cemptyset%5Chspace%7B10%20mm%7Dy%3A10%5Ctextbf%7Bg%7D-%5Ctextbf%7BT%7D_2%3D10%5Ctextbf%7Ba%7D" alt="" /></p>
<p>For the 3kg block, we have:</p>
<p><img src="http://joefilippazzo.com/wp-content/uploads/2008/08/3kg_block.jpg" title="free body diagram for the 3kg block" width="180" /></p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=x%3A%5Ctextbf%7BT%7D_1-.2%5Ctextbf%7BN%7D_1%3D3%5Ctextbf%7Ba%7D" alt="" /></p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=y%3A%5Ctextbf%7BN%7D_1-3%5Ctextbf%7Bg%7D%3D0%5Chspace%7B10%20mm%7Dso%2C%5Chspace%7B10%20mm%7D%5Ctextbf%7BN%7D_1%3D3%5Ctextbf%7Bg%7D%3D(3)(9.8)%3D29.4N" alt="" /></p>
<p>And for the 4kg block, we see the true beauty of the free body diagram. We can set our axes in any direction we choose so the equations don&#8217;t get mucked up with superfluous sines and cosines. In this case, we&#8217;ll rotate the xy-axes by -30º and call the axes x´and y´:</p>
<p><img src="http://joefilippazzo.com/wp-content/uploads/2008/08/4kg_block.jpg" title="free body diagram for the 4kg block" width="180" /></p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=x%5Cprime%3A%20%5Ctextbf%7BT%7D_2-%5Ctextbf%7BT%7D_1-.1%5Ctextbf%7BN%7D_2-4%5Ctextbf%7Bg%7Dsin(30)%3D4%5Ctextbf%7Ba%7D"  /></p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=y%5Cprime%3A%20%5Ctextbf%7BN%7D_2-4%5Ctextbf%7Bg%7Dcos(30)%3D0%5Chspace%7B10%20mm%7Dso%2C%5Chspace%7B10%20mm%7D%5Ctextbf%7BN%7D_2%3D4%5Ctextbf%7Bg%7Dcos(30)%3D33.94N"  /></p>
<p>We get values for <em><strong>N</strong><sub>1</sub></em> and <em><strong>N</strong><sub>2</sub></em> right off the bat where <em>N</em> is the unit of force called the Newton (not to be confused with <em><strong>N</strong></em>, the normal vector).</p>
<p>Now just add up all the results (&#8221;eff-equals-em-ey&#8221; is the <em>sum</em> of all forces) and solve for <em><strong>a</strong></em>:</p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=%5Ctextbf%7BT%7D_1-(.2)(29.4)%3D3%5Ctextbf%7Ba%7D%0A%5C%5C(10)(9.8)-%5Ctextbf%7BT%7D_2%3D10%5Ctextbf%7Ba%7D%0A%5C%5C%5Cunderline%7B%5Ctextbf%7BT%7D_2-%5Ctextbf%7BT%7D_1-(.1)(33.94)-(4)(9.8)(.5)%3D4%5Ctextbf%7Ba%7D%7D%0A%5C%5C98-5.88-3.39-19.6%3D17%5Ctextbf%7Ba%7D"  /></p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=%5Ctextbf%7Ba%7D%3D%5Cfrac%7B69.13%7D%7B17%7D%3D4.07m%2Fs%5E2"  /></p>
<h3>newtonian gravity</h3>
<p>The equation of force for Newtonian Gravity is:</p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&#038;eq=%5Ctextbf%7BF%7D_g%3DG%5Cfrac%7Bm_1m_2%7D%7B%5Ctextbf%7Br%7D%5E2%7D" /></p>
<p>Where,</p>
<li class="bullet" /><strong><em>F</em></strong><sub>g</sub> is the force between a body of mass <em>m</em><sub>1</sub> and a body of mass <em>m</em><sub>2</sub>,</li>
<li class="bullet" /><em>G</em> is the gravitational constant (6.67 × 10<sup>-</sup>&sup1;&sup1;&nbsp;N&middot;m&sup2;&middot;kg<sup>-</sup>&sup2;),</li>
<li class="bullet" />and <strong><em>r</em></strong> is the distance between the two bodies.</li>
<p>If an orbiting body with mass <em>M</em> has a period &#964;, the relationship between the period and the radius of two bodies is:</p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&#038;eq=%5Ctextbf%7Bv%7D%3D%5Cfrac%7B2%5Cpi%5Ctextbf%7Br%7D%7D%7B%5Ctau%7D%3D%5Csqrt%7B%5Cfrac%7BGM%7D%7B%5Ctextbf%7Br%7D%7D%7D%5Chspace%7B5%20mm%7Dso%2C%5Chspace%7B5%20mm%7DGM%3D%5Cfrac%7B4%5Cpi%5E2%5Ctextbf%7Br%7D%5E3%7D%7B%5Ctau%5E2%7D%5Chspace%7B5%20mm%7Dthus%2C%5Chspace%7B5%20mm%7D%5Ctextbf%7Br%7D%5E3%3D(%5Cfrac%7BGM%7D%7B4%5Cpi%5E2%7D)%5Ctau%5E2" /></p>
<p>Which brings us to:</p>
<ul><strong>Kepler&#8217;s Laws:</strong></p>
<li>Orbits are elliptical with two foci; one being the mass <em>M</em></li>
<li>An orbiting body covers equal area in equal time</li>
<li><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&#038;eq=%5Cfrac%7B%5Ctextbf%7Br%7D_1%5E3%7D%7B%5Ctextbf%7Br%7D_2%5E3%7D%3D%5Cfrac%7B%5Ctau_1%5E2%7D%7B%5Ctau_2%5E2%7D" /></li>
</ul>
<h3>ex: <span style="color: green">Bang, zoom, straight to the moon!</span></h3>
<p><strong>At what distance between the Earth and the Moon does a body have no net acceleration due to gravity?</strong></p>
<p><img src="http://joefilippazzo.com/wp-content/uploads/2008/08/pow_zoom.jpg" alt="" title="Ex: Bang, zoom, straight to the Moon!" width="375" /></p>
<p>So the free body diagram at the point looks very simple:</p>
<p><img src="http://joefilippazzo.com/wp-content/uploads/2008/08/pow_zoom_fbd.jpg" title="Earth/Moon free body diagram" width="175" /></p>
<p>Since there is no net acceleration, the forces to the left and right should be equal, giving:</p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&#038;eq=%5Ctextbf%7BF%7D_E%3D%5Ctextbf%7BF%7D_M%3DG%5Cfrac%7BM_E%5Chspace%7B1%20mm%7Dm%7D%7B%5Ctextbf%7Bx%7D%5E2%7D%3DG%5Cfrac%7BM_M%5Chspace%7B1%20mm%7Dm%7D%7B(%5Ctextbf%7BR%7D-%5Ctextbf%7Bx%7D)%5E2%7D%5Chspace%7B5%20mm%7Dso%2C%5Chspace%7B5%20mm%7D%5Cfrac%7BM_E%7D%7B%5Ctextbf%7Bx%7D%5E2%7D%3D%5Cfrac%7BM_M%7D%7B(%5Ctextbf%7BR%7D-%5Ctextbf%7Bx%7D)%5E2%7D" /></p>
<p>Here, <em>m</em> is the mass of the thing at the point (it could be an asteroid, a taco, whatever) but you don&#8217;t have to worry about it since it cancels. Plugging in the values for the mass of the Earth, the mass of the Moon and the distance between their centers, we get:</p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&#038;eq=(1-%5Cfrac%7BM_M%7D%7BM_E%7D)%5Ctextbf%7Bx%7D%5E2-2%5Ctextbf%7BRx%7D%2B%5Ctextbf%7BR%7D%5E2%3D0" /></p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&#038;eq=(1-%5Cfrac%7B7.35%5Ctimes10%5E%7B22%7Dkg%7D%7B5.97%5Ctimes10%5E%7B24%7Dkg%7D)%5Ctextbf%7Bx%7D%5E2-2(3.84%5Ctimes10%5E8m)%5Ctextbf%7Bx%7D%2B(3.84%5Ctimes10%5E8m)%5E2%3D0" /></p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&#038;eq=(.988)%5Ctextbf%7Bx%7D%5E2-(7.68%5Ctimes10%5E8)%5Ctextbf%7Bx%7D%2B(1.47%5Ctimes10%5E%7B17%7D)%3D0" /></p>
<p>Using the quadratic formula, we get the positive and negative roots:</p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&#038;eq=x_%7B%5Cpm%7D%3D(7.68%5Ctimes10%5E8)%5Cpm%5Cfrac%7B%5Csqrt%7B(5.9%5Ctimes10%5E%7B17%7D)-4(.988)(1.47%5Ctimes10%5E%7B17%7D)%7D%7D%7B2(.988)%7D" /></p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&#038;eq=x_%2B%3D4.36%5Ctimes10%5E8m%5Chspace%7B10%20mm%7Dand%5Chspace%7B10%20mm%7Dx_-%3D3.41%5Ctimes10%5E8m" /></p>
<p>The answer must be the negative root since the positive root is larger than <strong><em>R</em></strong>. That means that the position at which an asteroid, taco, whatever would feel no net acceleration from the Earth or the Moon is:</p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&#038;eq=x%3D3.41%5Ctimes10%5E8(%5Cfrac%7BR%7D%7B3.84%5Ctimes10%5E8%7D)%3D.89R" /></p>
<p>That&#8217;s nine-tenths the distance from the Earth to the Moon. POW, right in the kisser!</p>
<h2><a href="http://joefilippazzo.com/problem-set-3/" /> </a></p>
<ul class="gray" /><a href="http://joefilippazzo.com/problem-set-3/" />Problem Set 3 &raquo; Newton&#8217;s Laws</a></ul>
</h2>
]]></content:encoded>
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		</item>
		<item>
		<title>Kinematics</title>
		<link>http://joefilippazzo.com/2008/kinematics/</link>
		<comments>http://joefilippazzo.com/2008/kinematics/#comments</comments>
		<pubDate>Tue, 01 Jul 2008 20:57:26 +0000</pubDate>
		<dc:creator>Joe</dc:creator>
		
		<category><![CDATA[Classical Mechanics]]></category>

		<category><![CDATA[cylindrical coordinates]]></category>

		<category><![CDATA[dimensional analysis]]></category>

		<category><![CDATA[equations of motion]]></category>

		<category><![CDATA[τ (period)]]></category>

		<category><![CDATA[projectile motion]]></category>

		<category><![CDATA[spherical coordinates]]></category>

		<category><![CDATA[uniform cirular motion]]></category>

		<guid isPermaLink="false">http://joefilippazzo.com/?p=21</guid>
		<description><![CDATA[Kinematics is not actually physics in the truest sense since it only answers the “how” of an arbitrary equation, not the “why” of the system’s behavior. Here's an overview that includes dimensional analysis and the equations of motion in cartesian, cylindrical and spherical coordinates.]]></description>
			<content:encoded><![CDATA[<h3>Dimensional Analysis</h3>
<p>First, let&#8217;s do a super-fast review of dimensional analysis since it will be your best method of spot checking your calculations, not to mention a handy way of guessing answers on <a href="http://joefilippazzo.com/archives/4">obnoxiously long multiple-choice tests</a>.</p>
<p>When solving for a variable in an equation, dimensional analysis will tell you if you&#8217;re on the right track or not. For example, an object with initial position, initial velocity and acceleration (in one direction) of <em>x<sub>o</sub></em>, <em>v<sub>0</sub></em> and <em>a</em> respectively, can be found at a time <em>t</em> by the equation:</p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=x%3Dx_o%2Bv_ot%2B%5Cfrac%7B1%7D%7B2%7Dat%5En%20%20%20" alt="null" /></p>
<p>Regardless of the equation&#8217;s significance, we need the value of <em>n</em>.</p>
<p>Using dimensional analysis, or by doing &#8220;normal math&#8221; on the units, we can find out very quickly. So,</p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=m%3Dm%2B%5Cfrac%7Bm%7D%7Bs%7Ds%2B%5Cfrac%7B1%7D%7B2%7D%5Cfrac%7Bm%7D%7Bs%5E2%20%7Ds%5En%3Dm%2Bm%2Bm%5Cfrac%7Bs%5En%20%7D%7Bs%5E2%7D" alt="null" /></p>
<p>Since <em>x</em> must be in meters, the seconds must cancel, so <em>n</em> must be 2. For absolutely any equation, just jot down the units and cancel everything you can.</p>
<h3>Equations of Motion in Cartesian Coordinates</h3>
<p>Kinematics is not actually physics in the truest sense since it only answers the &#8220;how&#8221; of an arbitrary equation, not the &#8220;why&#8221; of the system&#8217;s behavior. But damnit, it&#8217;s useful.</p>
<p>The instantaneous velocity of an object as a function of time is given by an infinitesimal change in position over an infinitesimal period of time or:<br />
<em>v(t) = <sup>dx</sup>/<sub>dt</sub></em></p>
<p>The instantaneous acceleration is just the derivative of the velocity, or an infinitesimal change in velocity over an infinitesimal period of time:<br />
<em>a(t) = <sup>dv</sup>/<sub>dt</sub></em></p>
<p>And keep in mind that any variable with <sub>0</sub> (phonetically &#8220;nawt&#8221;) means the initial value (t = 0).</p>
<p id="eqofmotion">
<ul><strong>Here are the kinematic equations of motion:</strong></p>
<li><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=%5Ctextbf%7Bv%7D%3D%5Ctextbf%7Bv%7D_0%2B%5Ctextbf%7Ba%7Dt" alt="" /></li>
<li><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=%5Ctextbf%7Bv%7D%5E2%3D%5Ctextbf%7Bv%7D_0%5E2%2B2%5Ctextbf%7Ba%7D(%5Ctextbf%7Bx%7D-%5Ctextbf%7Bx%7D_0)" alt="" /></li>
<li><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=%5Ctextbf%7Bx%7D%3D%5Ctextbf%7Bx%7D_0%2B%5Ctextbf%7Bv%7D_0t%2B%5Cfrac%7B1%7D%7B2%7D%5Ctextbf%7Ba%7Dt%5E2" alt="" /></li>
<li><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=%5Ctextbf%7Bx%7D%3D%5Ctextbf%7Bx%7D_0%2B%5Cfrac%7B1%7D%7B2%7D(%5Ctextbf%7Bv%7D_0%2B%5Ctextbf%7Bv%7D)t" alt="" /></li>
</ul>
<p>Keep in mind that there are only so many well-formed questions you can ask with these equations:</p>
<li class="bullet">t (v), (What is the time when the velocity is v?)</li>
<li class="bullet">t (x), (What is the time when the position is x?)</li>
<li class="bullet">x (t), (What is the position at time t?)</li>
<li class="bullet">x (v), (What is the position at a velocity v?)</li>
<li class="bullet">v (x), (What is the velocity at a position x?)</li>
<li class="bullet">v (t), (What is the velocity at time t?)</li>
<h3>projectile motion</h3>
<p>Projectile motion is really just a special case of motion where the acceleration is constant. In the y-direction (+ up and - down), the force is a constant <strong>g</strong> (= -9.8 m/s² = the force of Earth&#8217;s gravity).</p>
<p>Here&#8217;s one example, but there are several more in <a href="http://joefilippazzo.com/problem-set-2/">Problem Set 2</a>.</p>
<h3>Example: <span style="color: green;">Swish!</span></h3>
<p><strong>What initial velocity is needed to make the shot?</strong></p>
<p><img class="aligncenter" title="Ex: Swish!" src="http://joefilippazzo.com/wp-content/uploads/2008/07/ex2-300x191.jpg" alt="" width="325" /></p>
<p>Well, the definition of making the shot is: x (y = 3) = 6<br />
Or, x (t = t<sub>swish</sub>) = 6 and y (t = t<sub>swish</sub>) = 3</p>
<p>First the x component:</p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=x%3Dx_0%2Bv_%7B0x%7Dt" alt="" /></p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=6%3D0%2Bv_0cos45(t_%7Bswish%7D)" alt="" /></p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=t_%7Bswish%7D%3D%5Cfrac%7B6%7D%7Bv_0%20cos45%7D" alt="" /></p>
<p>Then the y component:</p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=y%3Dy_0%2Bv_%7B0y%7Dt-gt%5E2" alt="" /></p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=3%3D%201.8%2Bv_0sin45(t_%7Bswish%7D)-4.9t%5E2" alt="" /></p>
<p>But we know the value of <em>t<sub>swish</sub></em> from our calculation of the x component.<br />
Just plug it in:</p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=3%3D1.8%2Bv_0sin45(%5Cfrac%7B6%7D%7Bv_0cos45%7D)-4.9(%7B%5Cfrac%7B6%7D%7Bv_0cos45%7D)%5E2%7D" alt="" /></p>
<p><img src="http://joefilippazzo.com/wp-content/uploads/2008/07/latex2png2.png" alt="" /></p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=-4.8%3D%5Cfrac%7B352.8%7D%7Bv_0%5E2%7D%5Chspace%7B10%20mm%7Dso%2C%5Chspace%7B10%20mm%7Dv_0%3D8.573m%2Fs" alt="" /></p>
<h3>uniform circular motion</h3>
<p>For uniform circular motion, it&#8217;s much easier to speak in terms of radii and angles instead of x and y components. Using the graph below, we&#8217;ll get our new variables.</p>
<p><img title="uniform circular motion" src="http://joefilippazzo.com/wp-content/uploads/2008/07/circularmotion.jpg" alt="" width="400" /></p>
<p>A particle moving in a circle of radius <em>r</em> will sweep an infinitesimal angle dθ and move a distance <em>s</em>. With constant velocities, we get:</p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=s%3Drsind%5Ctheta%3Drd%5Ctheta" alt="" /></p>
<p>(since sine of a very small angle is approximately equal to the angle)</p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=d%5Ctheta%3D%5Cfrac%7Bv%7D%7Br%7Ddt%5Cqquad%7Cdv%7C%3D%5Cfrac%7Bv%5E2%7D%7Br%7Ddt" alt="" /></p>
<p>And we get the centripetal acceleration of an object moving in a circle:</p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=%5Cfrac%7B%7Cdv%7C%7D%7Bdt%7D%3D%5Cfrac%7Bv%5E2%7D%7Br%7D%3D%5Ctextbf%7Ba%7D%3D%5Cfrac%7B4%5Cpi%5E2%5Ctextbf%7Br%7D%7D%7B%5Ctau%5E2%7D%5Chspace%7B10%20mm%7Dwhere%2C%5Chspace%7B10%20mm%7D%5Ctau%3D%5Cfrac%7B2%5Cpi%5Ctextbf%7Br%7D%7D%7B%5Ctextbf%7Bv%7D%7D" alt="" /></p>
<h3>Non-linear coordinate systems</h3>
<p>Using these radii and angles, we can construct a set of equations for rotational motion using <strong>cylindrical coordinates</strong>. And then, we can extrapolate to <strong>spherical coordinates</strong>!</p>
<ul><strong>The kinematic equations of rotational motion:</strong></p>
<li><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&#038;eq=%5Comega%3D%5Comega_0%2B%5Calpha%7Bt%7D" /></li>
<li><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&#038;eq=%5Comega%5E2%3D%5Comega_0%5E2%2B2%5Calpha%5Ctheta" /></li>
<li><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&#038;eq=%5Ctheta%3D%5Comega_0t%2B%5Cfrac%7B1%7D%7B2%7D%7B%5Calpha%7Dt%5E2" /></li>
<li><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&#038;eq=%5Ctheta%3D%5Cfrac%7B%5Comega_0%2B%5Comega%7D%7B2%7Dt" /></li>
</ul>
<p>Spherically speaking, the coordinates become:</p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&#038;eq=%5Cbegin%7Barray%7D%7Blll%7D%0Ar%3D%5Crho%5Csin%7B%5Cphi%7D%26x%3Dr%5Ccos%7B%5Ctheta%7D%26x%3D%5Crho%5Csin%5Cphi%5Ccos%7B%5Ctheta%7D%5C%5C%0A%5C%5C%0Az%3D%5Crho%5Ccos%7B%5Cphi%7D%26y%3Dr%5Csin%5Ctheta%26y%3D%5Crho%5Csin%5Cphi%5Csin%5Ctheta%5C%5C%0A%5C%5C%0A%5Ctheta%3D%5Ctheta%26z%3Dz%26z%3D%5Crho%5Ccos%5Cphi%0A%5Cend%7Barray%7D%0A"></p>
<h2><a href="http://joefilippazzo.com/problem-set-2/"> </a></p>
<ul class="gray"><a href="http://joefilippazzo.com/problem-set-2/">Problem Set 2 » Kinematics</a></ul>
</h2>
]]></content:encoded>
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		</item>
		<item>
		<title>Vectors</title>
		<link>http://joefilippazzo.com/2008/vectors/</link>
		<comments>http://joefilippazzo.com/2008/vectors/#comments</comments>
		<pubDate>Mon, 09 Jun 2008 05:45:48 +0000</pubDate>
		<dc:creator>Joe</dc:creator>
		
		<category><![CDATA[Classical Mechanics]]></category>

		<category><![CDATA[cross product]]></category>

		<category><![CDATA[dot product]]></category>

		<category><![CDATA[scalar triple product]]></category>

		<category><![CDATA[unit coordinate vectors]]></category>

		<category><![CDATA[vector triple product]]></category>

		<category><![CDATA[vectors]]></category>

		<guid isPermaLink="false">http://joefilippazzo.com/?p=16</guid>
		<description><![CDATA[What physics web site would be complete without a comprehensive treatment of vectors? Here's our vector algebra guide including dot, cross and triple products plus a bunch of examples.]]></description>
			<content:encoded><![CDATA[<p>A vector is just a set of numbers used to describe a single quantity (direction and magnitude) and from here on in, I&#8217;ll indicate a variable that is a vector by making it boldface. So the components of a vector <em><strong>a</strong></em> are:</p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=%5Ctextbf%7Ba%7D_x%3D%5Ctextbf%7Ba%7D%5Ccos%5Ctheta%5Chspace%7B10%20mm%7Dand%5Chspace%7B10%20mm%7D%5Ctextbf%7Ba%7D_y%3D%5Ctextbf%7Ba%7D%5Csin%5Ctheta" alt="" /></p>
<p>This means that each component is equal to the product of the vector&#8217;s magnitude and the cosine of the angle between the positive axis and the vector.</p>
<p>So the magnitude of the vector and the angle between the vector and the positive axis are, respectively,</p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=%7Ca%7C%3D%5Csqrt%7B%7Ba_x%7D%5E2%2B%7Ba_y%7D%5E2%7D" alt="" /></p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=%5Ctheta%3Dtan%5E%7B-1%7D%5Cfrac%7Ba_y%7D%7Ba_x%7D" alt="" /></p>
<h3>Vector Addition and Subtraction</h3>
<p>To add or subtract vectors, just add or subtract the components:</p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=%5Ctextbf%7Ba%7D%5Cpm%5Ctextbf%7Bb%7D%3D(a_x%2Ca_y%2Ca_z)%5Cpm(b_x%2Cb_y%2Cb_z)%3D(a_x%7B%5Cpm%7Db_x%2Ca_y%7B%5Cpm%7Db_y%2Ca_z%7B%5Cpm%7Db_z)" alt="" /></p>
<p>The geometric interpretation is similarly simple. If you start <strong>b</strong> where <strong>a</strong> ends, the sum <strong>a + b</strong> is given by the hypotenuse that makes triangle abc. And if you start <strong>a</strong> and <strong>b</strong> at the same point, the hypotenuse gives <strong>a — b</strong>. Easy!</p>
<p><img title="vector addition" src="http://joefilippazzo.com/wp-content/uploads/2008/06/vector_add.png" alt="" width="175" align="center" /><img title="vector subtraction" src="http://joefilippazzo.com/wp-content/uploads/2008/06/vector_sub.png" alt="" width="200" align="center" /></p>
<h3 id="vectormultiplication">Vector Multiplication</h3>
<p>There are two ways to multiply vectors and each has a nifty geometric interpretation as well.</p>
<p>The <strong>dot product</strong> of two vectors is a scalar and the rules are the same as vector addition (<strong>a</strong> • <strong>b</strong> = a<sub>x</sub>b<sub>x</sub> + a<sub>y</sub>b<sub>y</sub> + a<sub>z</sub>b<sub>z</sub>) but there&#8217;s a shortcut!</p>
<p>Since <strong>a</strong> and <strong>b</strong> both start at (0, 0, 0), it is easier to calculate the angle θ between them rather than struggle individually with the x, y and z components. We can rotate our axes so that <strong>a</strong> runs along the x axis and <strong>b</strong> lies in the xy-plane. This would make the components (a, 0, 0) and (b cos θ, b sin θ, 0). So,</p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=%5Ctextbf%7Ba%7D%5Ccdot%5Ctextbf%7Bb%7D%3Da_xb_x%3D%7C%5Ctextbf%7Ba%7D%7C%7C%5Ctextbf%7Bb%7D%7C%5Ccos%5Ctheta_%7Bab%7D" alt="" /></p>
<p><img class="alignleft" title="dot product" src="http://joefilippazzo.com/wp-content/uploads/2008/06/dot_product.jpg" alt="" width="200" /></p>
<p>That is, <strong>a</strong> • <strong>b</strong>, a scalar, is b times the portion of a that extends in the b direction.</p>
<p>Now&#8217;s a good a time as any to introduce the <strong>unit coordinate vectors</strong>. These are just vectors whose magnitudes are unity and whose directions run along the Cartesian axes.</p>
<p>The unit coordinate vectors are:</p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=%5Chat%7B%5Ctextbf%7Bi%7D%7D%3D(1%2C0%2C0)%5Chspace%7B10%20mm%7D%5Chat%7B%5Ctextbf%7Bj%7D%7D%3D(0%2C1%2C0)%5Chspace%7B10%20mm%7D%5Chat%7B%5Ctextbf%7Bk%7D%7D%3D(0%2C0%2C1)" alt="" /></p>
<p><img class="alignleft" title="unit coordinate vectors" src="http://joefilippazzo.com/wp-content/uploads/2008/07/unit_vectors.jpg" alt="" height="200" /></p>
<p>(Pronounced &#8220;eye-hat,&#8221; &#8220;jay-hat&#8221; and &#8220;kay-hat&#8221;) This lets us separate the direction of the vector from the magnitude. Now we can express any vector like so:</p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=%5Ctextbf%7Ba%7D%3D(a_x%2Ca_y%2Ca_z)%3D(a_x%2C0%2C0)%2B(0%2Ca_y%2C0)%2B(0%2C0%2Ca_z)%5C%5C%3Da_x(1%2C0%2C0)%2Ba_y(0%2C1%2C0)%2Ba_z(0%2C0%2C1)%5C%5C%3Da_x%5Chat%7B%5Ctextbf%7Bi%7D%7D%2Ba_y%5Chat%7B%5Ctextbf%7Bj%7D%7D%2Ba_z%5Chat%7B%5Ctextbf%7Bk%7D%7D" alt="" /></p>
<p>From the definitions of the unit coordinate vectors, we get the following relations:</p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=%5Chat%7B%5Ctextbf%7Bi%7D%7D%5Ccdot%5Chat%7B%5Ctextbf%7Bi%7D%7D%3D%5Chat%7B%5Ctextbf%7Bj%7D%7D%5Ccdot%5Chat%7B%5Ctextbf%7Bj%7D%7D%3D%5Chat%7B%5Ctextbf%7Bk%7D%7D%5Ccdot%5Chat%7B%5Ctextbf%7Bk%7D%7D%3D%7C%5Chat%7B%5Ctextbf%7Bi%7D%7D%7C%7C%5Chat%7B%5Ctextbf%7Bi%7D%7D%7C%5Ccos0%3D(1%2C0%2C0)(1%2C0%2C0)(1)%3D1%0A%5C%5C%5Chat%7B%5Ctextbf%7Bi%7D%7D%5Ccdot%5Chat%7B%5Ctextbf%7Bj%7D%7D%3D%5Chat%7B%5Ctextbf%7Bi%7D%7D%5Ccdot%5Chat%7B%5Ctextbf%7Bk%7D%7D%3D%5Chat%7B%5Ctextbf%7Bj%7D%7D%5Ccdot%5Chat%7B%5Ctextbf%7Bk%7D%7D%3D%7C%5Chat%7B%5Ctextbf%7Bi%7D%7D%7C%7C%5Chat%7B%5Ctextbf%7Bj%7D%7D%7C%5Ccos90%3D(1%2C0%2C0)(0%2C1%2C0)(0)%3D0" alt="" /></p>
<p>The <strong>cross product</strong> of two vectors is a vector. Written as a matrix, we have:</p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=%5Ctextbf%7Ba%7D%5Ctimes%5Ctextbf%7Bb%7D%3D%5Cleft(%5Cbegin%7Barray%7D%7Bccc%7D%5Chat%7B%5Ctextbf%7Bi%7D%7D%26%5Chat%7B%5Ctextbf%7Bj%7D%7D%26%5Chat%7B%5Ctextbf%7Bk%7D%7D%5C%5Ca_x%26a_y%26a_z%5C%5Cb_x%26b_y%26b_z%5Cend%7Barray%7D%5Cright)" alt="" /></p>
<p>To put this (or any) matrix into algebraic form, do the following to get your x, y, and z components. For each component in the top row (e.g. <strong>i</strong>) multiply diagonally to the right (e.g. <strong>i</strong>a<sub>y</sub>b<sub>z</sub>) and then to the left (e.g. <strong>i</strong>a<sub>z</sub>b<sub>y</sub>) and subtract the second from the first (e.g. <strong>i</strong>a<sub>y</sub>b<sub>z</sub> — <strong>i</strong>a<sub>z</sub>b<sub>y</sub>). Do this for all the components and evaluate. The above matrix then gives us:</p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=%5Ctextbf%7Ba%7D%5Ctimes%5Ctextbf%7Bb%7D%3D%5Ctextbf%7Bc%7D%3D%5Chat%7B%5Ctextbf%7Bi%7D%7D(a_yb_z-a_zb_y)%2B%5Chat%7B%5Ctextbf%7Bj%7D%7D(a_zb_x-a_xb_z)%2B%5Chat%7B%5Ctextbf%7Bk%7D%7D(a_xb_y-a_yb_x)" alt="" /></p>
<p>Geometrically speaking, the vector <strong>c</strong> that results from the cross product of vectors <strong>a</strong> and <strong>b</strong> has a magnitude given by the product of |a| and |b| times the sine of the angle from a to b, or |<strong>c</strong>| = ab sin θ.</p>
<p>The direction is given by the &#8220;right hand rule.&#8221; If you lay your right hand palm-up along <strong>a</strong>, then curl your fingers toward <strong>b</strong>, the resulting vector <strong>c</strong> is in the direction of your thumb. Take a look:</p>
<p><img class="alignleft" title="cross product" src="http://joefilippazzo.com/wp-content/uploads/2008/07/cross_product.jpg" alt="" height="200" /></p>
<ul><strong>Properties of the cross product:</strong></p>
<li><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=%5Ctextbf%7Ba%7D%5Ctimes%5Ctextbf%7Bb%7D%3D-%5Ctextbf%7Bb%7D%5Ctimes%5Ctextbf%7Ba%7D" alt="" /></li>
<li><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=%5Ctextbf%7Ba%7D%5Ctimes(%5Ctextbf%7Bb%7D%2B%5Ctextbf%7Bc%7D)%3D(%5Ctextbf%7Ba%7D%5Ctimes%5Ctextbf%7Bb%7D)%2B(%5Ctextbf%7Ba%7D%5Ctimes%5Ctextbf%7Bc%7D)" alt="" /></li>
<li><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=c%5Chspace%7B1mm%7D(%5Ctextbf%7Ba%7D%5Ctimes%5Ctextbf%7Bb%7D)%3D(c%5Chspace%7B1%20mm%7D%5Ctextbf%7Ba%7D)%20%5Ctimes%5Ctextbf%7Bb%7D%3D%5Ctextbf%7Ba%7D%5Ctimes(c%5Chspace%7B1%20mm%7D%5Ctextbf%7Bb%7D)" alt="" /></li>
<li><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=%7C%5Ctextbf%7Ba%7D%5Ctimes%5Ctextbf%7Bb%7D%7C%5E2%3Da%5E2b%5E2-(%5Ctextbf%7Ba%7D%5Ccdot%5Ctextbf%7Bb%7D)%5E2" alt="" /></li>
</ul>
<p>From this we get some more unit coordinate vector relations:</p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=%5Chat%7B%5Ctextbf%7Bi%7D%7D%5Ctimes%5Chat%7B%5Ctextbf%7Bi%7D%7D%3D%5Chat%7B%5Ctextbf%7Bj%7D%7D%5Ctimes%5Chat%7B%5Ctextbf%7Bj%7D%7D%3D%5Chat%7B%5Ctextbf%7Bk%7D%7D%5Ctimes%5Chat%7B%5Ctextbf%7Bk%7D%7D%3D%5Chat%7B%5Ctextbf%7Bi%7D%7D(0-0)%2B%5Chat%7B%5Ctextbf%7Bj%7D%7D(0-0)%2B%5Chat%7B%5Ctextbf%7Bk%7D%7D(0-0)%3D0" alt="" /></p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=%5Chat%7B%5Ctextbf%7Bi%7D%7D%3D%5Chat%7B%5Ctextbf%7Bj%7D%7D%5Ctimes%5Chat%7B%5Ctextbf%7Bk%7D%7D%3D-%5Chat%7B%5Ctextbf%7Bk%7D%7D%5Ctimes%5Chat%7B%5Ctextbf%7Bj%7D%7D%5C%5C%5Chat%7B%5Ctextbf%7Bj%7D%7D%3D%5Chat%7B%5Ctextbf%7Bk%7D%7D%5Ctimes%5Chat%7B%5Ctextbf%7Bi%7D%7D%3D-%5Chat%7B%5Ctextbf%7Bi%7D%7D%5Ctimes%5Chat%7B%5Ctextbf%7Bk%7D%7D%5C%5C%5Chat%7B%5Ctextbf%7Bk%7D%7D%3D%5Chat%7B%5Ctextbf%7Bi%7D%7D%5Ctimes%5Chat%7B%5Ctextbf%7Bj%7D%7D%3D-%5Chat%7B%5Ctextbf%7Bj%7D%7D%5Ctimes%5Chat%7B%5Ctextbf%7Bi%7D%7D" alt="" /></p>
<h3>Triple Products</h3>
<p>The <strong>scalar triple product</strong> is the dot product of two vectors (since a vector &#8220;crossed&#8221; with a vector is a vector), which is a scalar:</p>
<p><img src="http://www.sitmo.com/gg/latex/latex2png.2.php?z=100&amp;eq=%5Ctextbf%7Ba%7D%5Ccdot(%5Ctextbf%7Bb%7D%5Ctimes%5Ctextbf%7Bc%7D)%3D%5Cleft(%5Cbegin%7Barray%7D%7Bccc%7Da_x%26a_y%26a_z%5C%5Cb_x%26b_y%26b_z%5C%5Cc_x%26c_y%26c_z%5Cend%7Barray%7D%5Cright)%3D(%5Ctextbf%7Ba%7D%5Ctimes%5Ctextbf%7Bb%7D)%5Ccdot%5Ctextbf%7Bc%7D" alt="" /></p>
<p>Now we know that the dot and cross products may be interchanged in the scalar triple product.</p>
<p>The <strong>vector triple product</strong> comes in handy when evaluating rotating coordinate systems or the rotation of rigid bodies. But more on that later.</p>
<p>It can be shown that <strong>a</strong> × (<strong>b</strong> × <strong>c</strong>) = <strong>b</strong>(<strong>a</strong> • <strong>c</strong>) — <strong>c</strong>(<strong>a</strong> •  <strong>b</strong>) but that&#8217;s a hell of a lot of LaTeX code. Try it out!</p>
<p>By the way, this is cordially referred to as the &#8220;back minus cab&#8221; rule for obvious reasons.</p>
<h2><a href="http://joefilippazzo.com/problem-set-1/"> </a></p>
<ul class="gray"><a href="http://joefilippazzo.com/problem-set-1/">Problem Set 1 » Vectors</a></ul>
</h2>
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		<title>The Beast Itself</title>
		<link>http://joefilippazzo.com/2008/the-beast-itself/</link>
		<comments>http://joefilippazzo.com/2008/the-beast-itself/#comments</comments>
		<pubDate>Fri, 30 May 2008 06:47:46 +0000</pubDate>
		<dc:creator>Joe</dc:creator>
		
		<category><![CDATA[About the Physics GRE]]></category>

		<category><![CDATA[ETS]]></category>

		<category><![CDATA[GRE]]></category>

		<category><![CDATA[practice test]]></category>

		<guid isPermaLink="false">http://joefilippazzo.com/?p=4</guid>
		<description><![CDATA[If you're gearing up to take the physics GRE, here's a quick run-through of the test's structure, the topics covered and other basic information. Plus, there's a PDF of a full practice test and some score statistics.]]></description>
			<content:encoded><![CDATA[<p>Our main focus will be the GRE subject test but I hope that <strong>The Prodigal Physicist</strong> will act as a comprehensive guide for everyone. In regards to the test though, let&#8217;s look at what we&#8217;re up against.</p>
<p>The Physics GRE consists of 100 five-option multiple-choice questions (some of which are grouped and based on graphical elements or experimental data) and we are given 70 perspiration-drenched minutes to answer as many as possible. According to ETS, the mean score on tests given between July 1, 2000 and June 30, 2003 was a 660 out of 990 or 38.5 out of 100 correctly answered questions.</p>
<p>If you&#8217;re already getting antsy, here&#8217;s the <a href="http://www.ets.org/Media/Tests/GRE/pdf/Physics.pdf">full practice test (PDF)</a> offered by ETS, but we&#8217;ll go through specific problems with explanations, (hopefully) discussion and all that jazz.</p>
<p>The topics covered with corresponding percentages are listed below but you can jump to any category with the links in the left sidebar. As we cover each topic, a permalink will become available so you can jump right to the section.</p>
<p>The test contains:</p>
<ol>
<li><a href="http://joefilippazzo.com/category/classical-mechanics/">CLASSICAL MECHANICS</a> (20%) such as <a href="http://joefilippazzo.com/2008/kinematics">kinematics</a>, <a href="http://joefilippazzo.com/2008/newtons-laws/">Newton&#8217;s laws</a>, <a href="http://joefilippazzo.com/2008/work-and-energy">work and energy</a>, oscillatory motion, rotational motion about a fixed axis, dynamics of systems of particles, central forces and celestial mechanics, three-dimensional particle dynamics, Lagrangian and Hamiltonian formalism, non-inertial reference frames, elementary topics in fluid dynamics.</li>
<li>ELECTROMAGNETISM (18%) such as electrostatics, currents and DC circuits, magnetic fields in free space, Lorentz force, induction, Maxwell&#8217;s equations and their applications, electromagnetic waves, AC circuits, magnetic and electric fields in matter.</li>
<li>OPTICS AND WAVE PHENOMENA (9%) such as wave properties, superposition, interference, diffraction, geometrical optics, polarization, Doppler effect.</li>
<li>THERMODYNAMICS AND STATISTICAL MECHANICS (10%) such as the laws of thermodynamics, thermodynamic processes, equations of state, ideal gases, kinetic theory, ensembles, statistical concepts and calculation of thermodynamic quantities, thermal expansion and heat transfer.</li>
<li>QUANTUM MECHANICS (12%) such as fundamental concepts, solutions of the Schrödinger equation (including square wells, harmonic oscillators, and hydrogenic atoms), spin, angular momentum, wave function symmetry, elementary perturbation theory.</li>
<li>ATOMIC PHYSICS (10%) such as properties of electrons, Bohr model, energy quantization, atomic structure, atomic spectra, selection rules, black-body radiation, x-rays, atoms in electric and magnetic fields.</li>
<li>SPECIAL RELATIVITY (6%) such as introductory concepts, time dilation, length contraction, simultaneity, energy and momentum, four-vectors and Lorentz transformation, velocity addition.</li>
<li>LABORATORY METHODS (6%) such as data and error analysis, electronics, instrumentation, radiation detection, counting statistics, interaction of charged particles with matter, lasers and optical interferometers, dimensional analysis, fundamental applications of probability and statistics.</li>
<li>SPECIALIZED TOPICS (9%)
<ol>
<li>Nuclear and Particle physics such as nuclear properties, radioactive decay, fission and fusion, reactions, fundamental properties of elementary particles,</li>
<li>Condensed Matter such as crystal structure, x-ray diffraction, thermal properties, electron theory of metals, semiconductors, superconductors,</li>
<li>Miscellaneous such as astrophysics, mathematical methods, computer applications.</li>
</ol>
</li>
</ol>
<p>And the math topics covered in one form or another include single and multivariable calculus, coordinate systems (rectangular, cylindrical, and spherical), <a href="http://joefilippazzo.com/2008/vectors">vector algebra</a> and vector differential operators, Fourier series, partial differential equations, boundary value problems, matrices and determinants, and functions of complex variables.</p>
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